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Q: What is the answer of 25a exponent of 5 15a exponent of 4-35a exponent of 3-40a exponent of 3 10a divided by 5a?

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10a - 15 ÷ 5 Order of Operations makes the equation this: 10a - 3, which is in simplest form.

The exponent tells how many times the base is used as a factor. 23 = 2 x 2 x 2

10a+a

10a − 3 − 4a

to solve this expression: 10a-4(a+2) -> 10a-4(a)-4(2) -> 10a-4a-8 -> 6a-8

3x3x3+3/3

16

10a + 3a - 4a = 9a

144ka

100a2 - 49b2 is the difference of two perfect squares. Therefore, it is equal to the sum times the difference of the roots: (10a + 7b)(10a - 7b)

This is for an 85 turbo. If you are looking at the fuse box the first row of fuses are (top from left) Head lamp (R.Hand) 10A Head lamp (L.Hand)10A Head lamp motor (R.H)15A Head lamp motor (L.H)15A clearance illumination15A Room lamp 10A Auxillary driving lamp15A Hazard 10A Horn 10A Stop lamp 20A Air conditioning/ Blower (Two fuses) both 15A NEXT ROW Engine control 15A Fuel pump10A Meter 10A Turn signal 10A A/T control 10A Auto door lock 10A Theft warning 10A Audio 10A RR Wiper 10A FR Wiper 15A Cigarette lighter 15A Aircon control 10A NEXT ROW Fan Motor 20A RR Defogger (TWO FUSES) both 20A I went to a junk yard. They gave me a kick panel, it had the label. I would recommend that.

No, the voltage rating should not be exceeded. However, you could use a 250v 10a fuse for a 125v 10a fuse.

10a - 5b = 25 So 5b = 10a - 25 and hence b = 2a - 5

The GCF is 2a.

5/6 x 12 = (5 x 12)/6 = 60/6 = 10A sixth of 12 (12 divided by 6) is 2, so 5 sixths (5 times 2) would be 10

The expression is simplified to: 12f-(10a+5b)

12a + 4 - 10a = 2a + 4 or 2*(a + 2)

10a + 15 = 5 (2a + 3)

6a-10a=16 -4a=16 a=-4

It is 6a.

9

a 22yr old in only 10a your tiny

From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.

To multiply m x 10a by n x 10b: multiply the numbers (m x n) add the powers (a + b) (m x 10a) x (n x 10b) = mn x 10a+b To divide m x 10a by n x 10b: divide the numbers (m / n) subtract the powers (a - b) (m x 10a) / (n x 10b) = m/n x 10a-b

2a